A system has two failure modes. One failure mode, due to external conditions, has a constant failure rate of 0.07 failures per year. The second, attributed to wear out, has a Weibull distribution with a characteristic life of 10 yr and a shape parameter of 1.8. Determine the system reliability for a design life of 1 yr. (four decimals)

0.9177

Step-by-step explanation:

let us first represent the two failure modes with respect to time as follows

R₁(t) for external conditions

R₂(t) for wear out condition ( Wiebull )

Now,

where t = time in years = 1,

n = failure rate constant = 0.07

Also,

where t = time in years = 1

where Q = characteristic life in years = 10

and B = the shape parameter = 1.8

Substituting values into equation 1

Substituting values into equation 2

let the system reliability for a design life of one year be Rs(t)

hence,

Rs(t) = R1(t) * R2(t)

t = 1

Rs(1) = 0.9177 (approx to four decimal places)

step-by-step explanation:

if x = 2 you have to find x to finish the problem

what? ?

what type of question is thiss

step-by-step explanation: