Show, by shading, the area in the rectangle
which is closer to AB than to AD.

hey i’m new i won’t be answering any questions now bye peeps see you next time

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

y -5 = (-1/4)(x + 8)

step-by-step explanation:

54.864 meters

step-by-step explanation: