What is the slope of the line that contains the points (-3, 5) and (-5, 6)?

Slope m=-1/2

Step-by-step explanation:

The slope is m=dy/dx=(y2-y1)/(x2-x1), where index 1 refers to the first point (-3,5). The index 2 refers to the second point (-5,6).

We get:

m=(6-5)/((-5)-(-3))=1/(-5+3)=-1/2

- 1/2

Step-by-step explanation:

Slope = y2- y1/x2 - x1

Given

x1 = -3

y1 = 5

x2 = -5

y2 = 6

Therefore

Slope = 6 - 5 /-5 -(-3)

= 6-5/-5+3

= 1/-2

= - 1/2

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right