In a circle with a 12-inch radius, find the length of a segment joining the midpoint of a 20-inch chord and the center of the circle. x =

If we connect the center of the circle to the endpoint and midpoint of the chord, we form a right triangle with the hypotenuse equal to 12 inch, one of its sides is half of 20 inch and the other side unknown. Let x be this side,
                                      x² + 10² = 12²
The value of x is approximately equal to 6.63 in.

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The density of the cube is 40