Please help ASAP
The graph shows the distance a ball has traveled x seconds after it was thrown. What is the average speed between 2 seconds and 8 seconds. (there is a picture of the graph below)

Group of answer choices

2 meters per second

0.8 meters per second

0.5 meters per second

3meters per second

Question 2# The function below represents the height of an object when it is dropped from a height of 144 ft, where x is the number of seconds after release. What is the average speed (or average rate of change) during the first 2 seconds after release? f(x)=-16x^2+144

Rising at a rate of 32 feet per second

Falling at a rate of 32 feet per second

Falling at a rate of 144 feet per second

Rising at a rate of 80 feet per second

0.5 m/s

Falling at 32 feet/s

Step-by-step explanation:

For the first question, since it only asks for the average time between 2 and 8 seconds, those are the only two important values. When taking the inputs and outputs for 2 and 8 seconds after the throw ((2,3) and (8,6) respectively), we can take the average change by finding the change in y/change in x, so we have (6-3)/(8-2)=0.5 meters/second.

For the second question, we can similarly just take the values from the initial drop (144) and after two seconds (80) to get that the rate of change is (144-80)/(-2)=-32, so it's falling at 32 feet/second.

Let me know if you have any questions!

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

< 3

step-by-step explanation:

my answer is$ 12

step-by-step explanation:

because 15 -2=12