Write the equation in slope-intercept form of the line that is parallel to the
graph of each equation and passes through the given point.
1. y = 3x + 6; (4, 7)

I want to make sure im doing it right can anyone help?

the desired equation is y = 3x - 5

Step-by-step explanation:

The correct form of this equation is y = mx + b, where m is the slope and b is the y-intercept.

Any line parallel to the given y = 3x + 6 has an equation of exactly the same form except for the y-intercept (b = 6).

We must find an appropriate y-intercept.  To do this, substitute 4 for x and 7 for y in y = 3x + C:  7 = 3(4) + C, or 7 = 12 + C, or C = -5.

Then the desired equation is y = 3x - 5

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4