Write the equation in slope-intercept form of the line that is parallel to the
graph of each equation and passes through the given point.
1. y = 3x + 6; (4, 7)

y = 3x - 5

Step-by-step explanation:

The given line, y = 3x + 6, has a slope of 3.  So does the new (desired) line:  

y = 3x + C.  We need to determine the y-intercept, C, for the line with slope 3 and passing through (4, 7):

7 = 3(4) + C, or 7 = 12 + C.  Then C = -5, and the desired equation is

y = 3x - 5

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

you have to put the graph on here with the question

step-by-step explanation: