A circle is centered at R(2,4)R(2,4)R, (, 2, comma, 4, ). The point L(0,8)L(0,8)L, (, 0, comma, 8, )is on the circle. Where does the point Q(6,7)Q(6,7)Q, (, 6, comma, 7, )lie?

The point Q(6,7) lie outside the circle.

Step-by-step explanation:

We know that, the general equation of a circle,

  ---------(1)

Centre is (-g, -f) = (2,4) (given)

So, -g = 2⇒g = -2

and, -f = 4⇒f = -4

Putting the value of g and f in equation(1), we get

The point L(0,8) is on the circle, the this point can satisfy the above equation.

So,

Now, the equation of circle is

Putting the and in the above equation, we get

5, which is greater than 0.

So, the point Q(6,7) lie outside the given circle.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

where r the answers

step-by-step explanation: