Mathematics, 24.03.2020 00:57 dd50

For her 1st birthday, Ruth's grandparents invested $1000 in an 18-year certificate for her that pays 10% compounded annually. How much will the certificate be worth on Ruth's 19th birthday? (Round your answer to the nearest cent.)

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Answer from: lanaiheart7

On Ruth's 19th birthday the certificate will be worth $ 5,559.91.

Given that for her 1st birthday, Ruth's grandparents invested $ 1000 in an 18-year certificate for her that pays 10% compounded annually, to determine how much will the certificate be worth on Ruth's 19th birthday the following calculation must be performed:

1000 x (1 + 0.1) ^ 18 = X 1000 x 1.1 ^ 18 = X 1000 x 5.55991 = X 5,559.91 = X

Therefore, on Ruth's 19th birthday the certificate will be worth $ 5,559.91.

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Answer from: anthonyvargas8780

The certificate will be worth $5,559.92 on Ruth's 19th birthday.

Step-by-step explanation:

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this problem, we have that:

P = 1000, n = 1, r = 0.1, t = 18

$A = 1000(1 + \frac{0.1}{1})^{1*18}$

A = 5559.92

The certificate will be worth $5,559.92 on Ruth's 19th birthday.

For her 1st birthday, Ruth's grandparents invested $1000 in an 18-year certificate for her that pays

Answer from: Quest

step-by-step explanation:

Answer from: Quest

the answer is 200

step-by-step explanation:

this is a problem about poisson probabilities. i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.

here's how you can see a poisson distribution coming. when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution. this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot. there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything. the form of the distribution is

probability of n chips = {[e^(-x)]*(x^n)} / (n! )

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