Suppose a class of 50 students has 20 males and 30 females. The insturctor will pick 1 (different) student to compete in 3 different national competitions--in mathematics, chemistry, and English. a. What is the probability that there is exactly 1 female student selected?b. What is the probability that there are at least 2 male students selected?

(a)0.2908

(b)0.349

Step-by-step explanation:

Total Number of Students=50

Number of Male Students=20

Number of Female Students=30

Note that the selection is without replacement as each student selected is different. Also the student could be picked for any of Mathematics, Chemistry or English competitions in that order.

(a)Probability of Picking exactly one female student.

P(Exactly one Female)= P(FMM) OR P(MFM) OR P(MMF)

Where P(FMM) means a female is selected for Mathematics, Male for Chemistry and Male for English respectively.

P(FMM) OR P(MFM) OR P(MMF)

=0.2908

(b)Probability that at least 2 male students are selected.

P(at least 2 male students are selected) = P(FMM) OR P(MFM) OR P(MMF) OR P(MMM)

P(MMM) =0.0582

Recall from Part (a) that:

P(FMM) OR P(MFM) OR P(MMF) =0.2908

Therefore:

P(at least 2 male students are selected) =0.2908+0.0582 =0.349

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

3030 ur welcome

step-by-step explanation: