An airplane travels 2416 kilometers against the wind in 4 hours and 2896 kilometers with the wind in the same amount of time. What's the rate of the plane in still air and what's the rate of the wind?

the rate of the plane in still air is 664 km/h and the rate of the wind is 60 km/h

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

An airplane travels 2416 kilometers against the wind in 4 hours. This means that the total speed with which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

2416 = 4(x - y)

Dividing both sides of the equation by 4, it becomes

604 = x + y- - - - - - - - - - - 1

It flew 2896 kilometers with the wind in the same amount of time.. This means that the total speed with which the plane flew with the wind is (x + y) mph.

Distance travelled by the plane while flying with the wind is

2896 = 4(x + y)

Dividing both sides of the equation by 2, it becomes

724 = x + y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

1328 = 2x

x = 1328/2

x = 664

Substituting x = 664 into equation 2, it becomes

724 = 664 + y

y = 724 - 664

y = 60

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

is there supposed to be a diagram or a graph for this one? ?

step-by-step explanation: