Write an equation of that passes through the points (-2,-3,) and (2,5)

y = 2x + 1

Step-by-step explanation:

Find the slope

( -2 , -3) ( 2 , 5)

m = (y2 - y1 )/(x2 - x1)

x1= -2

y1 = -3

x2 = 2

y2 = 5

m = 5 - (-3)/ ( 2 - (-2)

m = (5 + 3) / ( 2 + 2)

= 8/4

= 2

m = 2

Using the equation of a line

y = mx + c

y - intercept point y

m - slope of the line

x - intercept point x

c - intercept

Substitute m into the equation

y = 2x + c

Substitute any of the two points given into the equation

( 2 ,5 )

x - 2

y - 5

y = 2x + c

5 = 2(2) + c.

5 = 4 + c

c = 5 - 4

c = 1

The equation of the line

y = 2x + 1

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph