The ubiquitous 12oz aluminum cans used to distribute drinks in this country have a diameter of approximately 2.75 inches and a height of 5.0 inches. Estimate the amount of aluminum that could be saved if the cans were designed with the ratio d/h=1, while having the same volume as the standard 12oz can. Amount of aluminum saved, as a percentage of the amount used to make the optimal cans, equals

3.5%

Step-by-step explanation:

The volume of a cylinder =

r = radius of cylinder,

h = height of cylinder

For the non-optimal can,

r = 2.75/2 = 1.375

h = 5.0

For the optimal can,

d/h = 1,

d = h

2r = h

r = h/2

They have the same volume.

(This is the height of the optimal can)

(This is the radius of the optimal can)

The area of a cylinder is

For the non-optimal can,

For the optimal can,

Amount of aluminum saved, as a percentage of the amount used to make the optimal cans =

i don't even know man. edge inuity be messing with us. i had to ask a question too.

salary

step-by-step explanation: