Mathematics, 24.03.2020 07:34 ErrorNameTaken505
Find the time required for an investment of $3000 to grow to $9000 at an interest rate of 6.5% per year, compounded quarterly. (Round your answer to two decimal places.)
Answers: 2
![log(3)=log[(1.01625)^{4t}]](/tpl/images/0560/7584/53dce.png)
![t=log(3)/[4log(1.01625)]](/tpl/images/0560/7584/fabb1.png)
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Find the time required for an investment of $3000 to grow to $9000 at an interest rate of 6.5% per y...
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