Wo airplanes leave the airport. plane a departs at a 42° angle from the runway, and plane b departs at a 44° from the runway. which plane was farther away from the airport when it was 7 miles from the ground? round the solutions to the nearest hundredth.
plane a because it was 9.428 miles away
plane a because it was 10.46 miles away
plane b because it was 10.08 miles away
plane b because it was 9.73 miles away

plane a because it was 10.46 miles away

Step-by-step explanation:

We use the Sine Rule to determine which plane is further away after 7 miles off the ground.

#Plane A departs at 42°, The 7 mile flight corresponds to the 42°:

#Plane B departs at  44°,The 7 mile flight corresponds to the 42°:

Hence, Plane A since it's 10.46 miles away.

what are the options? ?

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1