Given m∠LON\qquad m \angle LON m∠LON m, angle, L, O, N is a straight angle. m∠LOM=4x+30∘\qquad m \angle LOM = 4x + 30^\circ m∠LOM=4x+30 ∘ m, angle, L, O, M, equals, 4, x, plus, 30, degrees m∠MON=8x+90∘\qquad m \angle MON = 8x + 90^\circ m∠MON=8x+90 ∘ m, angle, M, O, N, equals, 8, x, plus, 90, degrees Find m∠MONm\angle MON m∠MON m, angle, M, O, N : OO O LL L NN N MM M ∘{}^{\circ} ∘ degrees Show Calculator Stuck?Watch a video or use a hint. Report a problem

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

step-by-step explanation:

this is not a question

step-by-step explanation:

when the line is solid:

when the line is dashed:

this > inequality sign means:

this < inequality sign means:

this > inequality sign means:

this < inequality sign means:

about the problem:

srry i'm not done ! i'll

hello! just here for points! though i wish i knew!