Find the distance between (-5,2) and (-5,6)

Step-by-step explanation:

Distance between two points is given as

Let point 1 be (x1,y1)

Point 2 be (x2,y2)

So the distance between them is given as

d=√(x2-x1)²+(y2-y1)²

So, applying this to the given question

P1=(-5,2)

P2=(-5,6)

Therefore x1=-5 and y1=2

Also x2=-5 and y2=6

Then,

d=√(x2-x1)²+(y2-y1)²

d=√(-5--5)²+(6-2)²

Note -×-=+

d=√(-5+5)²+(4)²

d=√(0)²+16

d=√0+16

d=√16

Then, d= +4units or -4units

But distance cannot be negative.

So the distance between the two given point is 4units

d=4units

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)