Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero.

Steps Reasons
1. a over b plus c over d Given
2. ad over bd plus cb over bd Multiply to get a common denominator
3. Simplify

Fill in the missing step in the proof.
ad times cb all over bd
ad plus cb all over bd
ad minus cb all over bd
ad plus cb all over two times bd

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

d

step-by-step explanation:

dont think so

step-by-step explanation:

eve and marks ratios are equivalent

step-by-step explanation: