Find an equation for the line that passes through the points (5, 2) and (-3,6).

y = -1/2x + 6

Step-by-step explanation:

Find the slope

( 5 , 2) ( -3 , 6)

m =( y2 - y1 )/ ( x2 - x1)

x1 = 5

y1 = 2

x2 = -3

y2 = 6

m = ( 6 -2)/(-3 - 5)

m = 4/-8

m = - 1/2

Substitute m into the equation of a line

y = mx + c.

y = -1/2x + c

Substitute any of the two points given into the equation

Let's pick (2 ,5)

x = 2

y = 5

y = -1/2x + c

5 = -1/2(2) + c

5 = -1*2/2 + c

5 = -2/2 + c

5 = -1 + c

c = 5 + 1

c = 6

y = -1/2x + 6

The equation of the line is

y = -1/2x + 6

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)