The perimeter of this rectangle and area, and if the area was 100 what would the value of x be, also if the area is 200, what is the value of x. thank you so much to whoever answers

Given:

Length of the rectangle = x + 21

Width of the rectangle = 5

To find:

Perimeter and area of the rectangle

Solution:

Perimeter =

Perimeter units

Area = length × width

Area square units

Substitute perimeter is 100 and find the value of x:

Subtract 52 from both sides.

Divide by 2 on both sides, we get

x = 24

Substitute area is 200 and find the value of x:

Subtract 105 from both sides.

Divide by 5 on both sides, we get

x = 19

If the perimeter is 100, then the value of x is 24.

If the area is 200, then the value of x is 19.

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!