I'm thinking of a three digit number it is an odd multiple of threes and the product of its digits 24. It is larger than 15^2. What are all the numbers I could be thinking of

243, 381, 423, 813, 831

Step-by-step explanation:

The product of its digits is 24, so we have opptions:

1,3,8 because 1*3*8=24

1,4,6 becaus 1*4*6=24

2,3,4 because 2*3*4=24

2,2,6 becaus 2*2*6=24

They can be divide by 3, so the sum of its digits can be divide by 3:

1+3+8=12 (It is OK)

1+4+6=11 (It is not ok)

2+3+4=9 (it is OK)

2+2+6=10 (it is not OK).

Now we have less opportunities, it is number of digits:

1,3,8 and 2,3,4.  In wich order we will se!:)

From the informations we know that three numbers are odd number and greater then 15*15=225

Therefore, for 1,3,8 it must be that  1 ro 3 is least digit (its odd number) that numbers are:

183, 813, 831, 381

greater then 225 are 381,831,813.

For digits 2,3,4 it must be that 3 is the least digit (number is odd) so we have:

243 and 423. Both are greater than 225.

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316