At a food bank a case of donated items contains 10 cans of soup, 8 cans of vegetables, and 8 cans of fruit. If 3 cans are selected at random to distribute, find the probability of getting 1 vegetable and 2 cans of fruit.

0.1385 or 13.85%

Step-by-step explanation:

Number of cans of soup (S) = 10

Number of cans of vegetables (V) = 8

Number of cans of fruit (F) = 8

Total number of cans (n) = 26

There are three possible ways to get 1 vegetable and 2 cans of fruit (VFF, FVF, FFV). If each outcome is equally likely, the probability is:

The probability is 0.1385 or 13.85%.

part a

in a city ice cream is mostly only bought when the temperature is very high as ice cream cools down our

so we can derive the conclusion that as the temperature increases the number of ice creams sold also increases

part b

y intercept is 5

slope is 2

happy to

pls mark as brainliest

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