Let h(t)= -16t^2+64t+80 represent the height of an object above the ground after t seconds. Determine the number of seconds it takes to achieve its maximum height.

2 seconds

Step-by-step explanation:

In this question, we are asked to calculate the the number of seconds it will take for an object to reach its maximum height given the equation of motion of the object in question.

At maximum height, we must know that the instantaneous y velocity becomes equal to zero. Now looking at the equation of motion in the question, what we need to do

Is to differentiate it with respect to t so as to get the information for the velocity.

dh(t)/dt = -32t + 64

At maximum height dh(t)/dt = 0

Hence -32t + 64 = 0

32t = 64

t= 64/32 = 2 acquiring all the banks in Nigeria

It will only take two seconds to hit maximum height

x-3y=4

step-by-step e