Mr. branson bought a total of 9 tickets to the zoo. he bought children tickes at the rate of 6.50 and adult tickts for 9.25 each. if he spent 69.50 altogether, how many adult tickets did mr. branson purchase

Mr. Branson bought 5 children tickets and 4 adult tickets.

Step-by-step explanation:

Let x be number of children tickets

Let y be the number of adult tickets.

So There are total of 9 tickets sold.

x+ y = 9 ------a

Cost of each child ticket = $ 6.50

Cost of an adult ticket = $ 9.25

6.5 x + 9.25 y = 69.5 ----b

Now we have to multiply equation a by -6.5 and add it eq. b as,

- 6.5 x-6.5 y = -58.5

6.5 x + 9.25 y = 69.5

x - term gets cancelled and we can write as,

9.25 y - 6.5 y = 69.5 - 58.5

2.75 y = 11

    y =

Plugin y = 4 in eq. a we will get x as,

x + y = 9

x+ 4 = 9

x = 9 - 4 = 5

So there are 5 children tickets and 4 adult tickets.

4 adult tickets did mr.branson purchase .

Step-by-step explanation:

Here we have , mr.branson bought a total of 9 tickets to the zoo. he bought children tickes at the rate of 6.50 and adult tickts for 9.25 each. if he spent 69.50 altogether, We need to find  how many adult tickets did mr.branson purchase . Let's find out:

Let Number of tickets of children & adult be x & y respectively so :

mr.branson bought a total of 9 tickets to the zoo i.e.

⇒      ...............(1)

he bought children tickes at the rate of 6.50 and adult tickts for 9.25 each. if he spent 69.50 altogether i.e.

⇒      ...............(2)

Multiplying equation (1) by 6.5 and then, subtracting equation (2) by (1):

⇒

⇒

⇒

⇒

⇒

Therefore , 4 adult tickets did mr.branson purchase .

thats not a system of equations, that is a solution