A rectangular container has a base that is 12 inches long and 8 inches wide. The container is filled with water to a height of 6 inches. If all the water is poured into a second container with a square base, it will rise to a height of 16 inches. What is the length of one edge of the square base of the second container?

the length of one edge of the square base of the second container is 6 inches.

Step-by-step explanation:

The formula for determining the volume of a rectangular container is expressed as

Volume = length × width × height

Considering the first container,

Length = 12 inches

Width = 8 inches

Height to which the water is filled is 6 inches.

Therefore, volume of water in the container is

12 × 8 × 6 = 576 inches³

Considering the second container,

Height of water = 16 inches

Let L represent the length of the square base. Then the area of the square base is L²

Volume of water would be 16L²

Since the water in the first container was poured into the second container, then

16L² = 576

L² = 576/16 = 36

L = √36

L = 6 inches

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

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