Suppose you have some wolves and some dogs. Dogs are named and wolves are not. If you call a dog it will run to you. A wolf would not. So, if you take care of a dog, then (in our pretend situation) you can let it run free. A wolf has to be caged all the time. Any pair of animals can fight, so you need to separate them. On a plane with one line you can place two dogs (one dog in each of the regions): they will not fight as they will be separated by a line, and they will run free. How many dogs and how many wolves can you place on a plane with three lines in general position?

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.

measurement of the swimming pool is given as = 7 yards 4.79 feet

first we will convert this to yards only.

1 foot = 0.33 yards

so, 4.79 feet = yards

so total yards are = yards

now we will convert this in meters.

1 yard = 0.914 meters

8.580 yards = meters

0.842 m = 0.842*100 = 84.2 cm

this becomes 7 meters and 84.2 cm

hence, the pool is 7 meters and 84.2 cm wide.