X2 + 8x + 6 (x2 + 8x + ) + 6 Erin was completing the square of the quadratic function in order to find the extreme value. What is the next step in the process, and what is the extreme value? A) (x + 8)2 - 58; the extreme minimum is -8 B) (x + 4)2 - 10; the extreme minimum is -4 C) (x2 + 8x + 16) + 6 - 16; the extreme minimum is -10 D) (x2 + 8x + 64) + 6 - 64; the extreme minimum is -58

C.

Step-by-step explanation:

The next step is to add (1/2 * 8)^2 = 4^2 = 16 to the 8x and subtract 16 from the + 6:

- to give (x^2 + 8x + 16) + 6 - 16 as the next step in the process.

The extreme minimum is  +6 - 16 = -10.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.