Find the equation of the line through the point (1,5) that is parallel to the line that passes through (2, 1) and (0, -5).

The answer to your question is  y = 3x + 2      

Step-by-step explanation:

Data

Point (1, 5)

Passes through  (2, 1) and (0, -5)

Process

1.- Calculate the slope of the parallel line

Formula

           m = (y2 - y1)/(x2 - x1)

-Substitution

           m = (-5 - 1)/ (0 - 2)

-Simplification

           m = -6/-2

-Result

           m = 3

As both lines are parallel, the slope is the same.

2.- Calculate the equation of the line

Formula

            y - y1 = m(x - x1)

-Substitution

            (y - 5) = 3(x - 1)

-Simplification

             y - 5 = 3x - 3

-Solve for y

                  y = 3x - 3 + 5

                  y = 3x + 2          

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: