Fund Raising. Suppose you have signed up for a bike-a-thon to raise money for charity. One person is sponsoring you at a rate of $0.50 per mile. Each of the other sponsors plans to donate $15 no matter how far your bike. a) Write a system of equations to model the donation d for m miles biked. b) For how many miles will all sponsors donate the same amount?

The system of equation is .

After 30 miles all the sponsors donate the same amount.

Step-by-step explanation:

Given:

Amount of donated by each of the other sponsors = $15

Amount donating by one person per mile = $0.5

We need to write the system of equation to model the donation d for m miles biked.

Also We need to find the number of miles all sponsors donate the same amount.

Solution:

Let the amount donated be denoted by 'd'.

Let number of miles biked be denoted by 'm'.

Now we know that;

Amount of donated by each of the other sponsors = $15

so we can say that;

Also We know that;

Amount donating by one person per mile = $0.5

So we can say that;

Hence The system of equation is .

Now to find the number of miles when all the sponsors donate the same amount we will make both the equation equal we get;

Dividing both side by 0.5 we get;

Hence After 30 miles all the sponsors donate the same amount.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.