What is the area of the parallelogram? The figure is not drawn to scale. (1 point)
1,720 in.2
1,240 in.2
142 in.2
71 in.2

Option B:

The area of the parallelogram is 1240 in²

Solution:

Base of the parallelogram = 40 in

Height of the parallelogram = 31 in

Area of the parallelogram = Base × Height

                                           = 40 × 31

                                           = 1240 in²

The area of the parallelogram is 1240 in².

Option B is the correct answer.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.