12x - 3y = 6 2x - y = 2

x = 0

y = -2

Step-by-step explanation:

to solve this simultaneous equation we are going to say

let

12x - 3y = 6 equation 1

2x - y = 2 equation 2

from equation 2

2x - y = 2 equation 2

2x - 2 = y

y = 2x - 2 equation 3

substitute the value of y into equation 1

12x - 3y = 6 equation 1

12x - 3( 2x -2) = 6

12x -6x + 6 = 6

6x + 6 = 6

6x = 6-6

6x = 0

divide both sides by 6

6x/6 = 0/6

x = 0

put the value of x = 0 into equation 3

y = 2x - 2 equation 3

y = 2(0) - 2

y = 0 - 2

y = -2

therefore from the solution the value of x is equal to zero(0) and the value of y is equal to -2 respectively.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

answer: idk wbu

step-by-step explanation: umm..