The 6-lb particle is subjected to the action of its weight and forces F1 = 52i + 6j - 2tk6 lb, F2 = 5t 2 i - 4tj - 1k6 lb, and F3 = 5 -2ti6 lb, where t is in seconds. Determine the distance the ball is from the origin 2 s after being released from rest.

r=294.9m

Step-by-step explanation:

The forces on the particle are

Now , we sum all these forces to get the net force

we can use the fact F=m*a and integrate the acceleration

and we evaluate in r(2) an we take the norm to obtain the distance

I hope this is useful for you

regards

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.