The formula for any geometric sequence is an = a1 · rn - 1, where an represents the value of the nth term, a1 represents the value of the first term, r represents the common ratio, and n represents the term number. What is the formula for the sequence -3, -6, -12, -24, ...?

an = -2 · (-3) n - 1
an = 2 · (-3) n - 1
an = -3 · 2 n - 1
an = -3 · (-2) n - 1

an = -3 · 2^n - 1

Step-by-step explanation:

In a geometric series, the consecutive terms differ by a common ratio. The formula for determining the nth term of a geometric progression is expressed as

an = a1 × r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

Looking at the given sequence,

a = - 3

r = - 6/ - 3 = 2

Therefore, the formula for the sequence is

an = - 3 × 2^(n - 1)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?