Suppose a teacher finds that the
scores of your students got on a quiz
inversely with the number of
absences they had.

If a student with 2 absences has a
score of 12, what would be the score
for a student who had three absences?
Reverse variation

Scores = 8

Step-by-step explanation:

To solve variation problems, you make mild assumptions and analogies

Let's score be represented with S

Let's Absences be represented with A.

Therefore

S varies inversely as A

S ~ 1/A

S = K/A

The K represents a contant notation so that we can easily figure the variation problem.

When Absences were 2

Scores were 12

S = K/A

12 = K / 2

Cross Multiply.

K = 24.

It means that, S = 24 / A.

For a student with 3 absences, the score would be:

S = 24 / A

S = 24 / 3

S = 8

Math is fun!

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.