Equation practice with angle addition
please help

∠MON = 57°

Step-by-step explanation:

∠MON = ∠LON - ∠LOM

(2x + 33°) = 113° - (3x + 20°)

2x + 33° = 113° - 3x - 20°

2x + 3x = 113° - 20° - 33°

5x = 60°

then

∠MON  = 2x + 33°

∠MON = 2(12) + 33°

∠MON  = 24 + 33°

∠MON = 57°

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

24/56=hx^7

step-by-step explanation: