Urgent answer please
Ax+ay+xa+ya

Possible derivation:

d/dx(a x + a y(x) + x a + y(x) a)

Rewrite the expression: a x + a y(x) + x a + y(x) a = 2 a x + 2 a y(x):

= d/dx(2 a x + 2 a y(x))

Differentiate the sum term by term and factor out constants:

= 2 a (d/dx(x)) + 2 a (d/dx(y(x)))

The derivative of x is 1:

= 2 a (d/dx(y(x))) + 1 2 a

Using the chain rule, d/dx(y(x)) = (dy(u))/(du) (du)/(dx), where u = x and d/(du)(y(u)) = y'(u):

= 2 a + d/dx(x) y'(x) 2 a

The derivative of x is 1:

= 2 a + 1 2 a y'(x)

Simplify the expression:

= 2 a + 2 a y'(x)

Simplify the expression:

 = 2 a

Step-by-step explanation:

step-by-step explanation: you take each of the numbers and divide by the amount then you take the range

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step-by-step explanation: