ABCD is a rectangle that represents a park.
The lines show all the paths in the park.
The circular path is in the centre of the
rectangle and has a diameter of 15 m.
Calculate the shortest distance from A to C
across the park, using only the lines shown.
50 m
80 m

The shortest distance from A to C is 102.89 meters

Step-by-step explanation:

step 1

Possibility N 1

The distance from A to C is equal to the length side AD plus the length side DC

so

step 2

Possibility 2

The distance from A to C is equal to the diagonal AC minus the diameter of the circle plus the semi-circumference of the circle

Find the diagonal AC

Applying the Pythagorean Theorem

Find the semi-circumference of the circle

we have

substitute

The distance  2 is equal to

therefore

The shortest distance from A to C is 102.89 meters

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