Find the value ofStartFraction partial derivative z Over partial derivative x EndFraction∂z∂xFind the value of at the point (1,1,1) if the equation 8xy+z"x- 2yz -7 defines z as a function of the two independent variables x and y and the partial derivative exists The value of dx at point (1,1,1) is□ Type an integer or a simplified fraction.)

The value of    at (1,1,1) is 1.

Step-by-step explanation:

Given,

wnere, z=f(x,y).

We have to find,

From (1) letting z'=m we get,

Integrate by letting we get,

Now differentiate partially with respect to x we get,

Letting and applying chain rule,

we get,

At (1,1,1),

Hence the result.

the third picture

step-by-step explanation:

i do not know the answer

step-by-step explanation: