Given that z is a standard normal random variable, find z for each situation. (Round your answers to two decimal places.) (a) The area to the right of z is 0.08. (b) The area to the right of z is 0.025. (c) The area to the right of z is 0.05. (d) The area to the right of z is 0.10.

Given that,

a)

P(z > z) = 0.08

1 - P (z  < z) = 0.08

P   (z  < z) = 1 - 0.08) = 0.92

P (z  < 1.41) = 0.92

z = 1.41

b)

P(z > z) = 0.025

1 - P (z  < z) = 0.025

P   (z  < z) = 1 - 0.025) = 0.975

P (z  < 1.96) = 0.975

z = 1.96

c)

P(z > z) = 0.05

1 - P (z  < z) = 0.05

P   (z  < z) = 1 - 0.05) = 0.95

P (z  < 1.65) = 0.95

z = 1.65

d)

P(z > z) = 0.10

1 - P (z  < z) = 0.10

P   (z  < z) = 1 - 0.10) = 0.9

P (z  < 1.28) = 0.9

z = 1.28

i believe the correct answer is option 4.principalities were small territories that were run by russian rulers.

which statement correctly defines principalities in northern asia in the 1200s? principalities were small territories that were run by russian rulers.

hope i could ! : )