What are the solutions of 12 – x2 = 0? x = 2 StartRoot 3 EndRoot and x = Negative 2 StartRoot 3 EndRoot x = 3 StartRoot 2 EndRoot and x = Negative 3 StartRoot 2 EndRoot x = 4 StartRoot 3 EndRoot and x = Negative 4 StartRoot 3 EndRoot x = 6 and x = –6

±2  sqrt(3) = x

Step-by-step explanation:

12 -x^2 =0

Add x^2 to each side

12 -x^2+x^2 =0+x^2

12 = x^2

Take the square root of each side

±sqrt(12) = sqrt(x^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

±sqrt(4*3) = sqrt(x^2)

±sqrt(4) * sqrt(3) = x

±2  sqrt(3) = x

i can't see the picture : /