A health spa offers holiday promotional treatment packages at a discount. Its recent tally for 4th of July holiday showed that 18% of the customers received seaweed wraps, 25% received shiatsu massages and 10% received both. What is the probability that a customer selected at random has received either seaweed wrap or shiatsu massage

Probability that a customer selected at random has received either seaweed wrap or shiatsu massage is 0.33.

Step-by-step explanation:

We are given that a health spa offers holiday promotional treatment packages at a discount. Its recent tally for 4th of July holiday showed that 18% of the customers received seaweed wraps, 25% received shiatsu massages and 10% received both.

Let Probability that customers received seaweed wraps = P(SW) = 0.18

Probability that customers received shiatsu massages = P(SA) = 0.25

Probability that customers received both seaweed wraps and shiatsu massages = = 0.10

Now, we have to find the probability that a customer selected at random has received either seaweed wrap or shiatsu massage.

So, probability that a customer selected at random has received either seaweed wrap or shiatsu massage is given by =

As we know that;

So, according to our question;

                                       = 0.18 + 0.25 - 0.10

                                       = 0.43 - 0.10 = 0.33

Hence, probability that a customer selected at random has received either seaweed wrap or shiatsu massage is 0.33.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x