What is the surface area of this square pyramid?

Round your answer to the nearest tenth, if necessary.

43.8 yd²
66.6 yd²
105 yd²
171.6 yd²

105 yd²

Step-by-step explanation:

The formula for determining the surface area of a square pyramid is expressed as

Surface area = base area + 2(length of each side × slant height)

From the information given,

Length of each side of the square = 6.2 yd

Base area = 6.2² = 38.44 yd²

To determine the slant height, h, we would apply the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side.

Adjacent side = 6.2/2 = 3.1

Opposite side = h

Therefore,

Tan 60 = h/3.1

h = 3.1tan60 = 3.1 × 1.732

h = 5.3692 yd

Therefore,

Surface area = 38.44 + 2(6.2 × 5.3692)

= 38.44 + 66.58

= 105yd² to the nearest tenth

105

Step-by-step explanation:

took the quiz

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?