An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an estimate at the 99%99% level of confidence. For a sample of 46574657 third graders, the mean words per minute read was 24.924.9. Assume a population standard deviation of 5.75.7. Construct the confidence interval for the mean number of words a third grader can read per minute. Round your answers to one decimal place.

99% confidence interval for the mean number of words a third grader can read per minute is [24.7 , 25.1].

Step-by-step explanation:

We are given that an educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an estimate at the 99% level of confidence. For a sample of 4657 third graders, the mean words per minute read was 24.9. Assume a population standard deviation of 5.7.

So, the pivotal quantity for 99% confidence interval for the mean number of words a third grader can read per minute is given by;

           P.Q. = ~ N(0,1)

where, = sample mean words per minute read = 24.9

             = population standard deviation = 5.7

            n = sample of third graders = 4657

             = population mean

So, 99% confidence interval for the population mean, is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99

P(-2.5758 < < 2.5758) = 0.99

P( < < ) = 0.99

P( < < ) = 0.99

99% confidence interval for = [ ,  ]

                                                = [ , ]

                                                = [24.7 , 25.1]

Therefore, 99% confidence interval for the mean number of words a third grader can read per minute is [24.7 , 25.1].

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: