Jason went shopping.
He bought a watch and a pair of trainers for a total price of £53.55.
This price includes a 15% loyalty discount.
Before the discount, the trainer's were priced at £38.
Work out the price of the watch before the discount.

The price of the watch before the discount is £33.4

Step-by-step explanation:

Let us assume,

The original price of the watch and a pair of trainers before the discount = x

⇒

⇒

⇒

⇒

The original price of a watch and a pair of trainers before the discount is £71.4

It is given that,

Before the discount, the trainer's were priced at £38

Before the discount, the total cost = trainer's cost + price of the watch.

⇒ 71.4 = 38 + price of the watch

⇒ Price of the watch = 71.4 - 38 = 33.4

∴ The price of the watch before the discount is £33.4

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

walter needs to make at least 5 more cookies but no more than 40. 5 ≤ x ≤ 40

step-by-step explanation:

20 ≤ x + 15 ≤ 55

subtract 15 from all parts

20-15 ≤ x + 15-15 ≤ 55-15

5 ≤ x ≤ 40

this means how many more cookies he has to make

walter needs to make at least 5 more cookies, but no more than 40 cookies; 5 ≤ x ≤ 40