A red ball and 4 white ball are in a box if two balls are drawn without replacement ,what is the probability of getting a red ball on the first drawn and a white ball on the second

The probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

Step-by-step explanation:

The two balls are drawn without replacement.

Drawing the first ball :

The first draw should be a red ball.

The probability to get a red ball = No.of red balls / Total balls in the box.

We know that, No. of red balls is 1 and total balls in the box is 5.

P(red ball) = 1/5

Drawing the second ball :

The second draw should be a white ball.

The probability to get white ball = No.of white balls / Total balls in the box.

We know that,

No. of white balls is 4.

The total balls in the box after the first draw will be 4 balls.

P(white ball) = 4/4

The probability of getting a red ball on the first drawn and a white ball on the second draw = P(red ball) × P(white ball)

⇒ (1/5) × (4/4)

⇒ 4/20

⇒ 1/5

Therefore, the probability is 1/5 to get a red ball in 1st draw and a white ball in 2nd draw.

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

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