The area of the rectangle is 3x2+6x-12square units. The length is x2+2x-4 What is the width of the rectangle?

delete for question misunderstood

Step-by-step explanation:

width (w) = 3

Step-by-step explanation:

The Area of a Rectangle = l * w

Where

l = length

w = width

From the question,

Area (A) = 3x²+6x-12

Length (l) = x² + 2x -4

To solve for width, let's rearrange the area.

A = 3x²+6x-12

A = 3 ( x²+ 2x -4)

From (A = lw)

Let's substitute the values:

3 ( x²+ 2x -4) = w * x² + 2x -4

Divide both sides by (x² + 2x -4)

3 = w.

Therefore, width (w) = 3

i think this could be a possible answer (1 / 84) -1

good luck! : d

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this