Tyler bought 3 calculators and 7 pens for $67.80. Barbara bought 6 calculators and 2 pens for $92.40. How much does each pen cost?

Each pen costs $3.6

Step-by-step explanation:

Solving Simultaneous equations by substitution method.

Step 1

Let us assume a calculator costs $C

Then, 3 calculators costs 3 X $C = $3C

And, 6 calculators costs 6 X $C = $6C

Also, let us assume a pen costs $P

Then, 7 pens cost 7 X $P = $7P

And 2 pens cost 2 X $P = $2P

Step 2

Tyler bought 3 calculators and 7 pens for 67.80

3C + 7P = 67.80

Barbara bought 6 calculators and 2 pens for 92.40

6C + 2P = 92.40

Step 3

The sentence gives us two equations that are simultaneous. We label the first equation as (1) and the second equation, equation (2)

3C + 7P = 67.80 (1)

6C + 2P = 92.40(2)

Step 4

Solve the simultaneous equations by substitution method.

In equation (1), we make C the subject

3C + 7P = 67.80 (1)

C = (67.80 - 7P) / 3

C = 22.60 - 7P/3(3)

Step 4

Substitute equation (3) into equation (2)

6C + 2P = 92.40(2)

6(22.60 - 7P/3) + 2P = 92.40

135.60 - 42P/3 + 2P = 92.40

Multiply through by 3

406.80 - 42P + 6P = 277.2

406.80 - 36P = 277.2

Collect like terms

406.80 - 36P - 406.80 = 277.2 - 406.80

-36P = -129.6

Divide both sides of the equation by -36

-36P/-36 = -129.6/-36

P = 3.6

Since P = cost of 1 pen, the cost of one pen is $3.6

2

step-by-step explanation:

1+1=2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐