Please i need help with this question. I will give brainliest answer

D

Step-by-step explanation:

Lets go equation by equation.

A) Is an upside down parabola shifted up 2 units. It will have to go downwards so its range is not greater than 2 (it is actually y < 2).

B) This is your regular old parabola, moved up two and shifted right 1. This means that since the graph is shifted up two, it will be y >= 2 (because the lowest point will be at y = 2).

C) This is a line shifted up 8 with a slope of 2. This will definitely go to infinity in both directions so it doesn't have a limited range.

D) This is an exponential graph shifted up two units. It will go beyond y = 2 and up to infinity. So, its range is y >2.

answer: -8.2562234e+13

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq