Jamie deposits $1,600 into two different savings accounts. Account I is compounded annually at an interest rate of 2.75%. Account II is a simple interest investment with a 3 1/2% interest rate. What is the difference between the two accounts after 2 years?

Step-by-step explanation:

Considering account I, we would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $1600

r = 2.75% = 2.75/100 = 0.0275

n = 1 because it was compounded once in a year.

t = 2 years

Therefore,

A = 1600(1 + 0.0275/12)^1 × 2

A = 1600(1.0275)^2

A = $1689.21

Considering account II, we would apply the formula for determining simple interest which is expressed as

I = PRT/100

Where

I represents interest paid on the investment.

P represents the principal or amount invested

R represents interest rate

T represents the duration of the investment in years.

From the information given,

P = 1600

R = 3.5

T = 2 years

I = (1600 × 3.5 × 2)/100 = $112

Total balance after 2 years is

112 + 1600 = $1712

the difference between the two accounts after 2 years is

1712 - 1689.21 = $22.79

the solution is 12x-6y

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: