Please answer the question correctly. I don't understand.
Which sets of side lengths represent Pythagorean triples? Check all that apply.
A. 1, 2, 5
B. 6, 8, 14
C. 8, 15, 17
D. 10, 24, 26
E. 15, 20, 30
F. 28, 45, 53

Some primitive triples are ...  (3, 4, 5)  (5, 12, 13)  (7, 24, 25)  (9, 40, 41)One interesting characteristic of these is that the sum of the last two numbers is the square of the first number.Any multiple of these will be a Pythagorean triple.Now consider your list.  a) (10, 24, 26) = 2×(5, 12, 13) . . . IS a Pythagorean Triple  b) 2×(7, 24, 25) = (14, 48, 50), so (14, 48, 49) is NOT a Pythagorean Triple  c) 3×(3, 4, 5) = (9, 12, 15), so (9, 12, 16) is NOT a Pythagorean Triple  d) (9, 40, 41) . . . IS a Pythagorean Triple  e) 5×(3, 4, 5) = (15, 20, 25) . . . IS a Pythagorean Triple The sets of side lengths that are Pythagorean Triples are ...  (10, 24, 26)  (9, 40, 41)  (15, 20, 25)

it is x=-4

step-by-step explanation:

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4